Web29 jan. 2012 · The answer is 0,0244 moles. How many moles is 573.28 g of AgCl? 4 How many moles of silver chloride are produced from 7 moles of silver nitrate? AgNO3 + … WebThe problem requires that you determine the mass of water, H2O, needed for the reaction to occur. CaCN2 (s) + 3 H2O (l) → CaCO3 (s) + 2 NH3 (g) 3 moles H2O/ 1 mole CaCN2. Assume 475 grams of acetylene, C2H2, reacts with oxygen, O2, to produce carbon dioxide, CO2, and water, H2O. The problem requires that you determine the mass of oxygen, O2 ...
How many moles is 573.28 g of AgCl? - Brainly.com
WebThe answer is 1 mole of AgCl. When 1 mole of AgNO3 and 2 moles of NaCl combine, 1 mole of AgCl is produced. I hope this helps. More answers below. Vasudevan A.N.S. … Web1 moles AgCl to grams = 143.3212 grams 2 moles AgCl to grams = 286.6424 grams 3 moles AgCl to grams = 429.9636 grams 4 moles AgCl to grams = 573.2848 grams 5 … grade 9 icse physics notes
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Web8 mrt. 2016 · 0.00048mol Moles = Mass/Molar mass n=m/M_r =0.0688/(107.87+35.5) =0.00048mol. Chemistry . ... How many moles are in .0688 g #AgCl#? Chemistry The … WebThe molecular formula for Silver Chloride is AgCl. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Silver Chloride, or 143.3212 grams. ... 4 moles Silver Chloride to grams = 573.2848 grams. 5 moles Silver Chloride to grams = 716.606 grams. 6 moles Silver Chloride to grams = 859.9272 grams. Web>> Mass of the solution of 1 molar glucose Question Calculate the number of mole of calcium chloride needed to react with excess silver nitrate to produce 8.61 g of AgCl. [Given : Molar mass of AgCl = 143.5 g) (A) 0.2 mol (B) 0.4 mol (C) 0.03 mol (D) 0.5 mol Solution Verified by Toppr Solve any question of Solutions with:- Patterns of problems > chilterns trail marathon